1/5(20-4a)=6-a

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Solution for 1/5(20-4a)=6-a equation: 



1/5(20-4a)=6-a

We move all terms to the left:

1/5(20-4a)-(6-a)=0



Domain of the equation: 5(20-4a)!=0

a∈R



We add all the numbers together, and all the variables

1/5(-4a+20)-(-1a+6)=0

We get rid of parentheses

1/5(-4a+20)+1a-6=0

We multiply all the terms by the denominator


1a*5(-4a+20)-6*5(-4a+20)+1=0

Wy multiply elements

5a^2(--30a(-+1=0

We use the square of the difference formula

5a^2(+30a(-1=0

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