1x+3(1x+2)=6-4(2x+3)

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Solution for 1x+3(1x+2)=6-4(2x+3) equation: 



1x+3(1x+2)=6-4(2x+3)

We move all terms to the left:

1x+3(1x+2)-(6-4(2x+3))=0

We add all the numbers together, and all the variables

1x+3(x+2)-(6-4(2x+3))=0

We add all the numbers together, and all the variables

x+3(x+2)-(6-4(2x+3))=0

We multiply parentheses

x+3x-(6-4(2x+3))+6=0



We calculate terms in parentheses: -(6-4(2x+3)), so:

6-4(2x+3)

determiningTheFunctionDomain
-4(2x+3)+6

We multiply parentheses

-8x-12+6

We add all the numbers together, and all the variables

-8x-6

Back to the equation:

-(-8x-6)



We add all the numbers together, and all the variables

4x-(-8x-6)+6=0

We get rid of parentheses

4x+8x+6+6=0

We add all the numbers together, and all the variables

12x+12=0

We move all terms containing x to the left, all other terms to the right

12x=-12

x=-12/12

x=-1

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