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X-3+1=5(2-X)
We move all terms to the left:
X-3+1-(5(2-X))=0
We add all the numbers together, and all the variables
X-(5(-1X+2))-3+1=0
We add all the numbers together, and all the variables
X-(5(-1X+2))-2=0
We calculate terms in parentheses: -(5(-1X+2)), so:We get rid of parentheses
5(-1X+2)
We multiply parentheses
-5X+10
Back to the equation:
-(-5X+10)
X+5X-10-2=0
We add all the numbers together, and all the variables
6X-12=0
We move all terms containing X to the left, all other terms to the right
6X=12
X=12/6
X=2
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