1x+2.5=(3x-2)/6

Solution for 1x+2.5=(3x-2)/6 equation:

1x+2.5=(3x-2)/6

We move all terms to the left:

1x+2.5-((3x-2)/6)=0

We add all the numbers together, and all the variables

x-((3x-2)/6)+2.5=0

We multiply all the terms by the denominator


x*6)-((3x-2)+(2.5)*6)=0

We add all the numbers together, and all the variables

x*6)-((3x-2)=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$