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1q/3+2/3=6
We move all terms to the left:
1q/3+2/3-(6)=0
determiningTheFunctionDomain 1q/3-6+2/3=0
We multiply all the terms by the denominator
1q+2-6*3=0
We add all the numbers together, and all the variables
q-16=0
We move all terms containing q to the left, all other terms to the right
q=16
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