1=d+19/3

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Solution for 1=d+19/3 equation: 



1=d+19/3

We move all terms to the left:

1-(d+19/3)=0

We add all the numbers together, and all the variables

-(+d+19/3)+1=0

We get rid of parentheses

-d+1-19/3=0

We multiply all the terms by the denominator


-d*3-19+1*3=0

We add all the numbers together, and all the variables

-d*3-16=0

Wy multiply elements

-3d-16=0

We move all terms containing d to the left, all other terms to the right

-3d=16

d=16/-3

d=-5+1/3

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