1/2b+3=17

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Solution for 1/2b+3=17 equation:



1/2b+3=17
We move all terms to the left:
1/2b+3-(17)=0
Domain of the equation: 2b!=0
b!=0/2
b!=0
b∈R
We add all the numbers together, and all the variables
1/2b-14=0
We multiply all the terms by the denominator
-14*2b+1=0
Wy multiply elements
-28b+1=0
We move all terms containing b to the left, all other terms to the right
-28b=-1
b=-1/-28
b=1/28

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