1=5(6+3v)-(7+4v)

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Solution for 1=5(6+3v)-(7+4v) equation: 



1=5(6+3v)-(7+4v)

We move all terms to the left:

1-(5(6+3v)-(7+4v))=0

We add all the numbers together, and all the variables

-(5(3v+6)-(4v+7))+1=0



We calculate terms in parentheses: -(5(3v+6)-(4v+7)), so:

5(3v+6)-(4v+7)

We multiply parentheses

15v-(4v+7)+30

We get rid of parentheses

15v-4v-7+30

We add all the numbers together, and all the variables

11v+23

Back to the equation:

-(11v+23)



We get rid of parentheses

-11v-23+1=0

We add all the numbers together, and all the variables

-11v-22=0

We move all terms containing v to the left, all other terms to the right

-11v=22

v=22/-11

v=-2

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