x+(x+3)=x2+21

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Solution for x+(x+3)=x2+21 equation: 



x+(x+3)=x2+21

We move all terms to the left:

x+(x+3)-(x2+21)=0

We add all the numbers together, and all the variables

-(+x^2+21)+x+(x+3)=0

We get rid of parentheses

-x^2+x+x-21+3=0

We add all the numbers together, and all the variables

-1x^2+2x-18=0

a = -1; b = 2; c = -18;
Δ = b2-4ac
Δ = 22-4·(-1)·(-18)
Δ = -68
Delta is less than zero, so there is no solution for the equation

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