1=3+(n/3)

Solution for 1=3+(n/3) equation:

1=3+(n/3)

We move all terms to the left:

1-(3+(n/3))=0

We add all the numbers together, and all the variables

-(3+(+n/3))+1=0

We multiply all the terms by the denominator


-(3+(+n+1*3))=0


We calculate terms in parentheses: -(3+(+n+1*3)), so:

3+(+n+1*3)

determiningTheFunctionDomain
(+n+1*3)+3

We add all the numbers together, and all the variables

(n+3)+3

We get rid of parentheses

n+3+3

We add all the numbers together, and all the variables

n+6

Back to the equation:

-(n+6)


We get rid of parentheses

-n-6=0

We add all the numbers together, and all the variables

-1n-6=0

We move all terms containing n to the left, all other terms to the right

-n=6

n=6/-1

n=-6