1=3(x-2)+(3-2x)

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Solution for 1=3(x-2)+(3-2x) equation: 



1=3(x-2)+(3-2x)

We move all terms to the left:

1-(3(x-2)+(3-2x))=0

We add all the numbers together, and all the variables

-(3(x-2)+(-2x+3))+1=0



We calculate terms in parentheses: -(3(x-2)+(-2x+3)), so:

3(x-2)+(-2x+3)

We multiply parentheses

3x+(-2x+3)-6

We get rid of parentheses

3x-2x+3-6

We add all the numbers together, and all the variables

x-3

Back to the equation:

-(x-3)



We get rid of parentheses

-x+3+1=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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