1=3(j-8)+-5

Solution for 1=3(j-8)+-5 equation:

1=3(j-8)+-5

We move all terms to the left:

1-(3(j-8)+-5)=0

We use the square of the difference formula

-(3(j-8)-5)+1=0


We calculate terms in parentheses: -(3(j-8)-5), so:

3(j-8)-5

We multiply parentheses

3j-24-5

We add all the numbers together, and all the variables

3j-29

Back to the equation:

-(3j-29)


We get rid of parentheses

-3j+29+1=0

We add all the numbers together, and all the variables

-3j+30=0

We move all terms containing j to the left, all other terms to the right

-3j=-30

j=-30/-3

j=+10