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1=2/3(10x+15)
We move all terms to the left:
1-(2/3(10x+15))=0
Domain of the equation: 3(10x+15))!=0We multiply all the terms by the denominator
x∈R
-(2+1*3(10x+15))=0
We calculate terms in parentheses: -(2+1*3(10x+15)), so:We add all the numbers together, and all the variables
2+1*3(10x+15)
determiningTheFunctionDomain 1*3(10x+15)+2
Wy multiply elements
3x(1+2
Back to the equation:
-(3x(1+2)
-(3x3=0
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