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(2x-3)/7=(3x/7)-2x
We move all terms to the left:
(2x-3)/7-((3x/7)-2x)=0
Domain of the equation: 7)-2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(2x-3)/7-((+3x/7)-2x)=0
We calculate fractions
=0
x=0/1
x=0
Równanie nie ma rozwiązania
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