1=1/8(40x+8)

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Solution for 1=1/8(40x+8) equation: 



1=1/8(40x+8)

We move all terms to the left:

1-(1/8(40x+8))=0



Domain of the equation: 8(40x+8))!=0

x∈R



We multiply all the terms by the denominator


-(1+1*8(40x+8))=0



We calculate terms in parentheses: -(1+1*8(40x+8)), so:

1+1*8(40x+8)

determiningTheFunctionDomain
1*8(40x+8)+1

Wy multiply elements

8x(4+1

Back to the equation:

-(8x(4+1)



We add all the numbers together, and all the variables

-(8x5=0

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