1=-3(w+2)+-2

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Solution for 1=-3(w+2)+-2 equation: 



1=-3(w+2)+-2

We move all terms to the left:

1-(-3(w+2)+-2)=0

We use the square of the difference formula

-(-3(w+2)-2)+1=0



We calculate terms in parentheses: -(-3(w+2)-2), so:

-3(w+2)-2

We multiply parentheses

-3w-6-2

We add all the numbers together, and all the variables

-3w-8

Back to the equation:

-(-3w-8)



We get rid of parentheses

3w+8+1=0

We add all the numbers together, and all the variables

3w+9=0

We move all terms containing w to the left, all other terms to the right

3w=-9

w=-9/3

w=-3

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