3(j+2)+1=10

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Solution for 3(j+2)+1=10 equation: 



3(j+2)+1=10

We move all terms to the left:

3(j+2)+1-(10)=0

We add all the numbers together, and all the variables

3(j+2)-9=0

We multiply parentheses

3j+6-9=0

We add all the numbers together, and all the variables

3j-3=0

We move all terms containing j to the left, all other terms to the right

3j=3

j=3/3

j=1

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