1=(t+13)/10+t

Solution for 1=(t+13)/10+t equation:

1=(t+13)/10+t

We move all terms to the left:

1-((t+13)/10+t)=0


Domain of the equation: 10+t)!=0

We move all terms containing t to the left, all other terms to the right

t)!=-10

t!=-10/1

t!=-10

t∈R


We multiply all the terms by the denominator


-((t+13)+1*10+t)=0


We calculate terms in parentheses: -((t+13)+1*10+t), so:

(t+13)+1*10+t

determiningTheFunctionDomain
(t+13)+t+1*10

We add all the numbers together, and all the variables

t+(t+13)+10

We get rid of parentheses

t+t+13+10

We add all the numbers together, and all the variables

2t+23

Back to the equation:

-(2t+23)


We get rid of parentheses

-2t-23=0

We move all terms containing t to the left, all other terms to the right

-2t=23

t=23/-2

t=-11+1/2