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19x-x2-84=0
We add all the numbers together, and all the variables
-1x^2+19x-84=0
a = -1; b = 19; c = -84;
Δ = b2-4ac
Δ = 192-4·(-1)·(-84)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-5}{2*-1}=\frac{-24}{-2} =+12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+5}{2*-1}=\frac{-14}{-2} =+7 $
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