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3(x+1)=2(5-2x)
We move all terms to the left:
3(x+1)-(2(5-2x))=0
We add all the numbers together, and all the variables
3(x+1)-(2(-2x+5))=0
We multiply parentheses
3x-(2(-2x+5))+3=0
We calculate terms in parentheses: -(2(-2x+5)), so:We get rid of parentheses
2(-2x+5)
We multiply parentheses
-4x+10
Back to the equation:
-(-4x+10)
3x+4x-10+3=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1
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