19x-19=2(6x-8)+7x-3

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Solution for 19x-19=2(6x-8)+7x-3 equation: 



19x-19=2(6x-8)+7x-3

We move all terms to the left:

19x-19-(2(6x-8)+7x-3)=0



We calculate terms in parentheses: -(2(6x-8)+7x-3), so:

2(6x-8)+7x-3

We add all the numbers together, and all the variables

7x+2(6x-8)-3

We multiply parentheses

7x+12x-16-3

We add all the numbers together, and all the variables

19x-19

Back to the equation:

-(19x-19)



We get rid of parentheses

19x-19x+19-19=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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