(3r+18)/9=(3r-24)/3

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Solution for (3r+18)/9=(3r-24)/3 equation: 



(3r+18)/9=(3r-24)/3

We move all terms to the left:

(3r+18)/9-((3r-24)/3)=0

We calculate fractions


3r/()+(-((3r-24)*9)/()=0



We calculate terms in parentheses: +(-((3r-24)*9)/(), so:

-((3r-24)*9)/(

We multiply all the terms by the denominator


-((3r-24)*9)



We calculate terms in parentheses: -((3r-24)*9), so:

(3r-24)*9

We multiply parentheses

27r-216

Back to the equation:

-(27r-216)



We get rid of parentheses

-27r+216

Back to the equation:

+(-27r+216)



We get rid of parentheses

3r/()-27r+216=0

We multiply all the terms by the denominator


3r-27r*()+216*()=0

We add all the numbers together, and all the variables

3r-27r*()=0

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