19=5(1+2x)+8(x-5)

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Solution for 19=5(1+2x)+8(x-5) equation: 



19=5(1+2x)+8(x-5)

We move all terms to the left:

19-(5(1+2x)+8(x-5))=0

We add all the numbers together, and all the variables

-(5(2x+1)+8(x-5))+19=0



We calculate terms in parentheses: -(5(2x+1)+8(x-5)), so:

5(2x+1)+8(x-5)

We multiply parentheses

10x+8x+5-40

We add all the numbers together, and all the variables

18x-35

Back to the equation:

-(18x-35)



We get rid of parentheses

-18x+35+19=0

We add all the numbers together, and all the variables

-18x+54=0

We move all terms containing x to the left, all other terms to the right

-18x=-54

x=-54/-18

x=+3

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