12x(x-5)=11(x+)

Solution for 12x(x-5)=11(x+) equation:

12x(x-5)=11(x+)

We move all terms to the left:

12x(x-5)-(11(x+))=0

We add all the numbers together, and all the variables

12x(x-5)-(11(+x))=0

We multiply parentheses

12x^2-60x-(11(+x))=0


We calculate terms in parentheses: -(11(+x)), so:

11(+x)

We multiply parentheses

11x

Back to the equation:

-(11x)


We add all the numbers together, and all the variables

12x^2-71x=0

a = 12; b = -71; c = 0;
Δ = b2-4ac
Δ = -712-4·12·0
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-71)-71}{2*12}=\frac{0}{24}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-71)+71}{2*12}=\frac{142}{24}
=5+11/12
$