19=3(z+-2)-7

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Solution for 19=3(z+-2)-7 equation: 



19=3(z+-2)-7

We move all terms to the left:

19-(3(z+-2)-7)=0

We add all the numbers together, and all the variables

-(3(z-2)-7)+19=0



We calculate terms in parentheses: -(3(z-2)-7), so:

3(z-2)-7

We multiply parentheses

3z-6-7

We add all the numbers together, and all the variables

3z-13

Back to the equation:

-(3z-13)



We get rid of parentheses

-3z+13+19=0

We add all the numbers together, and all the variables

-3z+32=0

We move all terms containing z to the left, all other terms to the right

-3z=-32

z=-32/-3

z=10+2/3

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