2(x-3)+7=3x-2(2x+1)

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Solution for 2(x-3)+7=3x-2(2x+1) equation: 



2(x-3)+7=3x-2(2x+1)

We move all terms to the left:

2(x-3)+7-(3x-2(2x+1))=0

We multiply parentheses

2x-(3x-2(2x+1))-6+7=0



We calculate terms in parentheses: -(3x-2(2x+1)), so:

3x-2(2x+1)

We multiply parentheses

3x-4x-2

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

-(-1x-2)



We add all the numbers together, and all the variables

2x-(-1x-2)+1=0

We get rid of parentheses

2x+1x+2+1=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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