19=3(s+3)+1

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Solution for 19=3(s+3)+1 equation: 



19=3(s+3)+1

We move all terms to the left:

19-(3(s+3)+1)=0



We calculate terms in parentheses: -(3(s+3)+1), so:

3(s+3)+1

We multiply parentheses

3s+9+1

We add all the numbers together, and all the variables

3s+10

Back to the equation:

-(3s+10)



We get rid of parentheses

-3s-10+19=0

We add all the numbers together, and all the variables

-3s+9=0

We move all terms containing s to the left, all other terms to the right

-3s=-9

s=-9/-3

s=+3

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