19-(2x-2)=2(x+3)+6x

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Solution for 19-(2x-2)=2(x+3)+6x equation: 



19-(2x-2)=2(x+3)+6x

We move all terms to the left:

19-(2x-2)-(2(x+3)+6x)=0

We get rid of parentheses

-2x-(2(x+3)+6x)+2+19=0



We calculate terms in parentheses: -(2(x+3)+6x), so:

2(x+3)+6x

We add all the numbers together, and all the variables

6x+2(x+3)

We multiply parentheses

6x+2x+6

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We add all the numbers together, and all the variables

-2x-(8x+6)+21=0

We get rid of parentheses

-2x-8x-6+21=0

We add all the numbers together, and all the variables

-10x+15=0

We move all terms containing x to the left, all other terms to the right

-10x=-15

x=-15/-10

x=1+1/2

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