(20x-3)+(11x-1)+29=180

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Solution for (20x-3)+(11x-1)+29=180 equation: 



(20x-3)+(11x-1)+29=180

We move all terms to the left:

(20x-3)+(11x-1)+29-(180)=0

We add all the numbers together, and all the variables

(20x-3)+(11x-1)-151=0

We get rid of parentheses

20x+11x-3-1-151=0

We add all the numbers together, and all the variables

31x-155=0

We move all terms containing x to the left, all other terms to the right

31x=155

x=155/31

x=5

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