19+x=15+3(x-2)

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Solution for 19+x=15+3(x-2) equation: 



19+x=15+3(x-2)

We move all terms to the left:

19+x-(15+3(x-2))=0



We calculate terms in parentheses: -(15+3(x-2)), so:

15+3(x-2)

determiningTheFunctionDomain
3(x-2)+15

We multiply parentheses

3x-6+15

We add all the numbers together, and all the variables

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

x-3x-9+19=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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