19+3y-1=12y-10-2y

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Solution for 19+3y-1=12y-10-2y equation:



19+3y-1=12y-10-2y
We move all terms to the left:
19+3y-1-(12y-10-2y)=0
We add all the numbers together, and all the variables
3y-(10y-10)+19-1=0
We add all the numbers together, and all the variables
3y-(10y-10)+18=0
We get rid of parentheses
3y-10y+10+18=0
We add all the numbers together, and all the variables
-7y+28=0
We move all terms containing y to the left, all other terms to the right
-7y=-28
y=-28/-7
y=+4

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