1=1/2(4y+2)

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Solution for 1=1/2(4y+2) equation: 



1=1/2(4y+2)

We move all terms to the left:

1-(1/2(4y+2))=0



Domain of the equation: 2(4y+2))!=0

y∈R



We multiply all the terms by the denominator


-(1+1*2(4y+2))=0



We calculate terms in parentheses: -(1+1*2(4y+2)), so:

1+1*2(4y+2)

determiningTheFunctionDomain
1*2(4y+2)+1

Wy multiply elements

2y(4+1

Back to the equation:

-(2y(4+1)



We add all the numbers together, and all the variables

-(2y5=0

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