19(4+2x)=33

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Solution for 19(4+2x)=33 equation: 



19(4+2x)=33

We move all terms to the left:

19(4+2x)-(33)=0

We add all the numbers together, and all the variables

19(2x+4)-33=0

We multiply parentheses

38x+76-33=0

We add all the numbers together, and all the variables

38x+43=0

We move all terms containing x to the left, all other terms to the right

38x=-43

x=-43/38

x=-1+5/38

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