7=3(2g-6)=29

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Solution for 7=3(2g-6)=29 equation: 



7=3(2g-6)=29

We move all terms to the left:

7-(3(2g-6))=0



We calculate terms in parentheses: -(3(2g-6)), so:

3(2g-6)

We multiply parentheses

6g-18

Back to the equation:

-(6g-18)



We get rid of parentheses

-6g+18+7=0

We add all the numbers together, and all the variables

-6g+25=0

We move all terms containing g to the left, all other terms to the right

-6g=-25

g=-25/-6

g=4+1/6

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