19(3-u)+11u=41

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Solution for 19(3-u)+11u=41 equation: 



19(3-u)+11u=41

We move all terms to the left:

19(3-u)+11u-(41)=0

We add all the numbers together, and all the variables

19(-1u+3)+11u-41=0

We add all the numbers together, and all the variables

11u+19(-1u+3)-41=0

We multiply parentheses

11u-19u+57-41=0

We add all the numbers together, and all the variables

-8u+16=0

We move all terms containing u to the left, all other terms to the right

-8u=-16

u=-16/-8

u=+2

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