2(2x+3)+(10x-5)=(5x-2)+(3x-0.5)

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Solution for 2(2x+3)+(10x-5)=(5x-2)+(3x-0.5) equation: 



2(2x+3)+(10x-5)=(5x-2)+(3x-0.5)

We move all terms to the left:

2(2x+3)+(10x-5)-((5x-2)+(3x-0.5))=0

We multiply parentheses

4x+(10x-5)-((5x-2)+(3x-0.5))+6=0

We get rid of parentheses

4x+10x-((5x-2)+(3x-0.5))-5+6=0



We calculate terms in parentheses: -((5x-2)+(3x-0.5)), so:

(5x-2)+(3x-0.5)

We get rid of parentheses

5x+3x-2-0.5

We add all the numbers together, and all the variables

8x-2.5

Back to the equation:

-(8x-2.5)



We add all the numbers together, and all the variables

14x-(8x-2.5)+1=0

We get rid of parentheses

14x-8x+2.5+1=0

We add all the numbers together, and all the variables

6x+3.5=0

We move all terms containing x to the left, all other terms to the right

6x=-3.5

x=-3.5/6

x=-1/1.7142857142857

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