19(12x+4)=23(7x+14)

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Solution for 19(12x+4)=23(7x+14) equation: 



19(12x+4)=23(7x+14)

We move all terms to the left:

19(12x+4)-(23(7x+14))=0

We multiply parentheses

228x-(23(7x+14))+76=0



We calculate terms in parentheses: -(23(7x+14)), so:

23(7x+14)

We multiply parentheses

161x+322

Back to the equation:

-(161x+322)



We get rid of parentheses

228x-161x-322+76=0

We add all the numbers together, and all the variables

67x-246=0

We move all terms containing x to the left, all other terms to the right

67x=246

x=246/67

x=3+45/67

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