4/3x+-7=2x-3

Solution for 4/3x+-7=2x-3 equation:

4/3x+-7=2x-3

We move all terms to the left:

4/3x+-7-(2x-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

4/3x-(2x-3)=0

We get rid of parentheses

4/3x-2x+3=0

We multiply all the terms by the denominator


-2x*3x+3*3x+4=0

Wy multiply elements

-6x^2+9x+4=0

a = -6; b = 9; c = +4;
Δ = b2-4ac
Δ = 92-4·(-6)·4
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{177}}{2*-6}=\frac{-9-\sqrt{177}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{177}}{2*-6}=\frac{-9+\sqrt{177}}{-12}
$