18n(2n+1)=11n-2(n+7)

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Solution for 18n(2n+1)=11n-2(n+7) equation: 



18n(2n+1)=11n-2(n+7)

We move all terms to the left:

18n(2n+1)-(11n-2(n+7))=0

We multiply parentheses

36n^2+18n-(11n-2(n+7))=0



We calculate terms in parentheses: -(11n-2(n+7)), so:

11n-2(n+7)

We multiply parentheses

11n-2n-14

We add all the numbers together, and all the variables

9n-14

Back to the equation:

-(9n-14)



We get rid of parentheses

36n^2+18n-9n+14=0

We add all the numbers together, and all the variables

36n^2+9n+14=0

a = 36; b = 9; c = +14;
Δ = b2-4ac
Δ = 92-4·36·14
Δ = -1935
Delta is less than zero, so there is no solution for the equation

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