4(j+5)=3(j-2)

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Solution for 4(j+5)=3(j-2) equation: 



4(j+5)=3(j-2)

We move all terms to the left:

4(j+5)-(3(j-2))=0

We multiply parentheses

4j-(3(j-2))+20=0



We calculate terms in parentheses: -(3(j-2)), so:

3(j-2)

We multiply parentheses

3j-6

Back to the equation:

-(3j-6)



We get rid of parentheses

4j-3j+6+20=0

We add all the numbers together, and all the variables

j+26=0

We move all terms containing j to the left, all other terms to the right

j=-26

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