18m(m+4/9)-16=118

Solution for 18m(m+4/9)-16=118 equation:

18m(m+4/9)-16=118

We move all terms to the left:

18m(m+4/9)-16-(118)=0

We add all the numbers together, and all the variables

18m(+m+4/9)-16-118=0

We add all the numbers together, and all the variables

18m(+m+4/9)-134=0

We multiply parentheses

18m^2+72m^2-134=0

We add all the numbers together, and all the variables

90m^2-134=0

a = 90; b = 0; c = -134;
Δ = b2-4ac
Δ = 02-4·90·(-134)
Δ = 48240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48240}=\sqrt{144*335}=\sqrt{144}*\sqrt{335}=12\sqrt{335}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{335}}{2*90}=\frac{0-12\sqrt{335}}{180}
=-\frac{12\sqrt{335}}{180}
=-\frac{\sqrt{335}}{15}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{335}}{2*90}=\frac{0+12\sqrt{335}}{180}
=\frac{12\sqrt{335}}{180}
=\frac{\sqrt{335}}{15}
$