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3x^2-1587=0
a = 3; b = 0; c = -1587;
Δ = b2-4ac
Δ = 02-4·3·(-1587)
Δ = 19044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19044}=138$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-138}{2*3}=\frac{-138}{6} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+138}{2*3}=\frac{138}{6} =23 $
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