18b2=2b

Solution for 18b2=2b equation:

18b^2=2b

We move all terms to the left:

18b^2-(2b)=0

a = 18; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·18·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*18}=\frac{0}{36}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*18}=\frac{4}{36}
=1/9
$