(34x/30+x)=3,2

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Solution for (34x/30+x)=3,2 equation: 



(34x/30+x)=3.2

We move all terms to the left:

(34x/30+x)-(3.2)=0



Domain of the equation: 30+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-30

x!=-30/1

x!=-30

x∈R



We add all the numbers together, and all the variables

(+x+34x/30)-(3.2)=0

We add all the numbers together, and all the variables

(+x+34x/30)-3.2=0

We get rid of parentheses

x+34x/30-3.2=0

We multiply all the terms by the denominator


x*30+34x-(3.2)*30=0

We add all the numbers together, and all the variables

34x+x*30-96=0

Wy multiply elements

34x+30x-96=0

We add all the numbers together, and all the variables

64x-96=0

We move all terms containing x to the left, all other terms to the right

64x=96

x=96/64

x=1+1/2

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