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18=18+(2f-40)/44+f)
We move all terms to the left:
18-(18+(2f-40)/44+f))=0
Domain of the equation: 44+f))+18!=0We multiply all the terms by the denominator
We move all terms containing f to the left, all other terms to the right
f))+18!=-44
f!=-44/1
f!=-44
f∈R
-(18+(2f-40)=0
We calculate terms in parentheses: -(18+(2f-40), so:We add all the numbers together, and all the variables
18+(2f-40
determiningTheFunctionDomain (2f-40+18
Back to the equation:
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| 8b+33=111 | | 3/x=4.2/92 | | -538=8(-9x+6) | | 10x-6=7x+19 | | 8-2(x+3)=3x-2(x-2) | | 2x=48–12x | | 1℅6m=5℅36 | | x+7=3x–13 | | 3(4x-12)=2(3x-4) | | 3(4x-12)=2(x-4) | | 105=240-3x | | 3x–(7+x)=2(x–1) | | 4x–5=13+x | | 3x.2x.x=600 | | 0,075x=24 | | 11=5+2·x | | x/2=8/3x | | 2x-x+13=27-3 | | 6x+4=15+5x | | 2|3+3k|4=71|12 | | 2x-13=7+x | | 2x-13=7+6 | | 50=5|4(3x-8) | | (15y–8y)+(16y–9y)=28 | | 15a-18=6a+16 | | -3|2a=7|3 | | 74=1,6x-12 | | s^2+4s+5=3 | | 9m2+30m+25=0 | | x0,2=40 | | 3,5+x=7,1 | | 3,5+x=7,1 |