8-2(x+3)=3x-2(x-2)

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Solution for 8-2(x+3)=3x-2(x-2) equation: 



8-2(x+3)=3x-2(x-2)

We move all terms to the left:

8-2(x+3)-(3x-2(x-2))=0

We multiply parentheses

-2x-(3x-2(x-2))-6+8=0



We calculate terms in parentheses: -(3x-2(x-2)), so:

3x-2(x-2)

We multiply parentheses

3x-2x+4

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We add all the numbers together, and all the variables

-2x-(x+4)+2=0

We get rid of parentheses

-2x-x-4+2=0

We add all the numbers together, and all the variables

-3x-2=0

We move all terms containing x to the left, all other terms to the right

-3x=2

x=2/-3

x=-2/3

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