18=-3(22-z)+3(z-4)

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Solution for 18=-3(22-z)+3(z-4) equation: 



18=-3(22-z)+3(z-4)

We move all terms to the left:

18-(-3(22-z)+3(z-4))=0

We add all the numbers together, and all the variables

-(-3(-1z+22)+3(z-4))+18=0



We calculate terms in parentheses: -(-3(-1z+22)+3(z-4)), so:

-3(-1z+22)+3(z-4)

We multiply parentheses

3z+3z-66-12

We add all the numbers together, and all the variables

6z-78

Back to the equation:

-(6z-78)



We get rid of parentheses

-6z+78+18=0

We add all the numbers together, and all the variables

-6z+96=0

We move all terms containing z to the left, all other terms to the right

-6z=-96

z=-96/-6

z=+16

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