18=(3/4)(2w-1)

Solution for 18=(3/4)(2w-1) equation:

18=(3/4)(2w-1)

We move all terms to the left:

18-((3/4)(2w-1))=0


Domain of the equation: 4)(2w-1))!=0

w∈R


We add all the numbers together, and all the variables

-((+3/4)(2w-1))+18=0

We multiply parentheses ..

-((+6w^2+3/4*-1))+18=0

We multiply all the terms by the denominator


-((+6w^2+3+18*4*-1))=0


We calculate terms in parentheses: -((+6w^2+3+18*4*-1)), so:

(+6w^2+3+18*4*-1)

We get rid of parentheses

6w^2+3-1+18*4*

We add all the numbers together, and all the variables

6w^2

Back to the equation:

-(6w^2)


a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{-12}=0$