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-186=6x(-2x-21)
We move all terms to the left:
-186-(6x(-2x-21))=0
We calculate terms in parentheses: -(6x(-2x-21)), so:We get rid of parentheses
6x(-2x-21)
We multiply parentheses
-12x^2-126x
Back to the equation:
-(-12x^2-126x)
12x^2+126x-186=0
a = 12; b = 126; c = -186;
Δ = b2-4ac
Δ = 1262-4·12·(-186)
Δ = 24804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24804}=\sqrt{36*689}=\sqrt{36}*\sqrt{689}=6\sqrt{689}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-6\sqrt{689}}{2*12}=\frac{-126-6\sqrt{689}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+6\sqrt{689}}{2*12}=\frac{-126+6\sqrt{689}}{24} $
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