189=(x+12)x

Solution for 189=(x+12)x equation:

189=(x+12)x

We move all terms to the left:

189-((x+12)x)=0


We calculate terms in parentheses: -((x+12)x), so:

(x+12)x

We multiply parentheses

x^2+12x

Back to the equation:

-(x^2+12x)


We get rid of parentheses

-x^2-12x+189=0

We add all the numbers together, and all the variables

-1x^2-12x+189=0

a = -1; b = -12; c = +189;
Δ = b2-4ac
Δ = -122-4·(-1)·189
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-30}{2*-1}=\frac{-18}{-2}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+30}{2*-1}=\frac{42}{-2}
=-21
$